Calculating force nessary to compress spring

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To calculate the force necessary to compress a spring by 3.6 cm, Hooke's Law (F = kx) is applied, where k is the spring constant (30 N/m) and x is the compression distance (0.036 m). This results in a force of 1.08 N. Additionally, using Newton's second law (F = ma), the deceleration caused by this force on a 0.12 kg mass is calculated to be 9 m/s². The discussion highlights the application of fundamental physics principles in solving the problem. The participant successfully completed their homework with the provided assistance.
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The data for a ball and spring sensor is given below:
mass of ball = 0.12kg
spring constant = 30Nm-1
distance to be compressed = 3.6cm

Calculate the force nessary to compress spring by 3.6cm.
The deceleration which the force in (the 1st question) would cause in a mass of 0.12kg.

i seem to find this question quite tricky, mainly becasue I am not sure of what equation to use!
please me on this one!
 
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What does Hooke's law tell you about springs and Newton's 2nd law tell you about acceleration?
 
yay! i got it! thanks for your help much appreciated!
and that's my homework done!
 
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