Calculating Force of Gravity with Fg = (G m1 Me)/Re^2

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The equation Fg = (G m1 Me)/Re^2 for calculating gravitational force does not account for the Earth's non-spherical shape, its elliptical orbit, or drag forces encountered in space. While these factors are acknowledged, only the Earth's shape significantly impacts the calculation of gravitational force. The equation also overlooks the Earth's varying density, particularly the differences between continental and oceanic crusts, which affects their buoyancy on the mantle. Although the Earth's rotation introduces a latitude-dependent centrifugal force, it primarily influences the measured weight of objects rather than the gravitational force itself. Overall, while the equation simplifies complex realities, its core application remains valid for calculating gravity.
Lucky_69
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does the following equation

Fg = (G m1 Me)/Re^2

the R is the radius had to get the e subscript

neglect the fact that

the Earth isn't really a sphere?

that the Earth dosen't move in a complete circular orbit?

That the Earth experiances a drag force among others as it moves through space?

That the Earth spins and that it experiances a latitude-dependent centrifugal force?
 
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Yes, to all of them. However only the first is of any significance. The others do not effect the force of gravity in any way. The last will effect the measured weight of a body but not the Earth's gravity.
 
It also neglects the fact that the density of the Earth is inconsistent. Perhaps the largest inconsistency in density is that continental crust has more silicon dioxide which is lighter and therefore floats higher on the semi-molten mantle, while oceanic crust is more dense, contains more magnesium and iron (which makes basalt black), so the oceanic crust floats lower on the mantle.
 
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