Calculating Force of Link 2 on Link 1 in Chain of 5 Links

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To calculate the force that link 2 exerts on link 1 in a chain of five links, each weighing 0.100 kg and accelerating upwards at 2.50 m/s², the total mass of links 2 to 5 (0.400 kg) must be considered. The force exerted by link 2 on link 1 includes both the gravitational force and the force due to the upward acceleration. The gravitational force acting on the combined mass is 3.92 N (0.400 kg * 9.8 m/s²), and the force from acceleration is 1 N (0.400 kg * 2.50 m/s²). Therefore, the total force exerted by link 2 on link 1 is approximately 4.92 N. This calculation is essential for understanding the dynamics of the chain under acceleration.
emilinus
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umm this question seems simple enough but I don't really know what I'm doing...

A chain consisting of 5 links, each of mass .100 kg is lifted vertically upwards with a constant acceleration of 2.50 m/s^2. Calculate the force that link 2 exerts on link 1.

so what I did was add the masses of links 2-5 (m=0.4 kg) and multiply this by the acceleration.

so my answer is F21 = 1 N
I have no idea if this is even close to what I'm supposed to do.
Help would be appreciated, thanks.
 
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Assuming the arrangement from top to bottom is 1-2-3-4-5, and the force accelerating them upward is tied to link 1, then link 1 is pulling on the combined mass of links 2, 3, 4 and 5. So there is the weight due to gravity and the force imposed by the acceleration of 2.5 m/s2.
 
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