Calculating Force: Swimming Pool Problem

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The discussion focuses on calculating the force exerted by water in a swimming pool with dimensions 30.0 m by 10.0 m and a depth of 2.00 m. The initial calculation for the force on the bottom of the pool is derived using buoyancy principles, resulting in a force of 5,880,000 N. For the sides and ends, there is uncertainty about the correct approach, with suggestions to consider average pressure and Bernoulli's equation. The average pressure formula is proposed as (p*g*h)/2, leading to the application of P=F*A for further calculations. Clarification on these methods is sought to accurately determine the forces on the pool's sides and ends.
ernay
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Homework Statement


A swimming pool has dimensions 30.0 m and 10.0 m and a flat bottom. When the pool is filled to a depth of 2.00 m with fresh water, what is the force caused by the water on the bottom? On each end? On each side?


Homework Equations


B = pgV
P1+pgh+1/2pv2


The Attempt at a Solution


For the force on the bottom I thought it'd make sense to use buoyancy, so basically (103)*9.8**30*10*2), which is 5,880,000N... As for the sides and ends, I haven't got a clue on how to do it, I thought it might've involved Bernoulli's equation but I'm not really sure..
 
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I've been looking around online and I've seen similar problems where they use average pressure... which is (p*g*h)/2 p is density btw... is this the right approach, then just use P=F*A?
 
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