Calculating Forces and Friction in a Two-Block System with a Spring

AI Thread Summary
A 30 kg block rests on a table with a 15 kg block on top, connected to a spring with a constant of 325 N/m. The coefficients of kinetic and static friction are 0.600 and 0.900, respectively. A force is applied to the lower block to maintain constant speed. Users are encouraged to share their attempts and specific points of confusion for better assistance. The discussion emphasizes the importance of understanding the spring's attachment and the forces involved.
Leata
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Homework Statement



a 30 kg is restin on a flat horizontal table. on top of this block rests a 15 kg block, to which a horizontal spring is attached, as shown in the drawing. the spring constant is 325N/m. the coefficient of kinetic friction between the lower block and the table is 0.600, and the coefficient of static friction between the two block is 0.900. a force F is applied to the lower block. this force is increasing in such a way as to keep the the blocks moving in a constant speed

Homework Equations


F=kx
Fk=usmg
Fs=usmg


The Attempt at a Solution


im clueless don't know where to start. please help guys
 
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Welcome to PF!

Hi Leata! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(oh, and what is the spring attached to?? :confused:)
 

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