Calculating Forces in Truss Members using Method of Section

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Discussion Overview

The discussion revolves around calculating forces in truss members using the Method of Section, focusing on determining reaction forces at supports and the internal forces within truss members. It includes aspects of homework problem-solving and technical reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The participant presents initial calculations for reaction forces at supports A and B, suggesting a vertical reaction force of 4000N upwards at A and 6000N upwards at B.
  • Forces in various truss members are calculated, with specific values proposed for members AC, AF, BK, and BE.
  • Another participant confirms the correctness of the initial calculations, expressing approval.
  • Further calculations for forces in members FC and FG are discussed, with the participant proposing a force of 5000N for FC based on the sine component and a force of -3002N for FG based on the cosine component.
  • A later reply corrects the value for FG to -3000N, questioning the implications of the negative sign.
  • Participants clarify that a negative force indicates compression while a positive force indicates tension.

Areas of Agreement / Disagreement

There is general agreement on the correctness of the initial calculations, but some uncertainty remains regarding the exact values for forces in members FC and FG, particularly the interpretation of the negative sign in the context of tension and compression.

Contextual Notes

Some calculations rely on specific angles and trigonometric relationships, which may not have been fully detailed. The discussion does not resolve all mathematical steps or assumptions made in the calculations.

Who May Find This Useful

Students and practitioners interested in structural engineering, mechanics, or those studying truss analysis methods may find this discussion relevant.

Mattmiles
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Homework Statement



a) Find the reactions provided by the foundations at A and B.
b) Use the method of Resolution at the Joints to calculate the forces in all the members.
c) Which member will fail first and why ?

Homework Equations



ƩFx = 0
ƩFy = 0
ƩM = 0

The Attempt at a Solution



I am really just concerned with whether I have got the following correct. If I have, then I have grasped the concept if not then if someone could point me in the right direction and advise me on where to go next of what I am doing wrong I would be very grateful.

Horizontal Reaction Forces in the X direction at point A = 0
Vertical Reaction Forces in the Y direction at A = 4000N Upwards
Reaction Forces about the moment A at point B = 6000 Newtons Upwards

Forces in Member AC = 0N (0 + AC + AF = 0)
Forces in Member AF = 4000N in Compression (4000 + AC + AF = 0)
Forces in Member BK = 6000N in Compression (6000 + FBK.Sin(90) + FBE = 0)
Forces in Member BE = 0N (-FBE + FBK = 0)

Thanks
 

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This is all good, you got them all correct:smile::approve::cool:
 
Thanks very much! One last thing. I am now finding the forces in Members FC and FG. Am I right in saying:

Forces in direction:
-(-4000) - FC x sin(53.1) = 0 and then I just rearrange for FC = 5000 Newtons

and now I know FC I can do the following:

Force in direction:
0 + (FC x cos(53.1)) + FG = 0 and again rearrange for FG = -3002 Newtons
 
Mattmiles said:
Thanks very much! One last thing. I am now finding the forces in Members FC and FG. Am I right in saying:

Forces in direction:
-(-4000) - FC x sin(53.1) = 0 and then I just rearrange for FC = 5000 Newtons
yes , compression or tension?
and now I know FC I can do the following:

Force in direction:
0 + (FC x cos(53.1)) + FG = 0 and again rearrange for FG = -3002 Newtons
You have a round off error, these are 3-4-5 right triangles, FG = -3000 N. What does the minus sign mean?
 
Sorry a negative number means it is compression and a positive number means it is in tension.
 
Mattmiles said:
Sorry a negative number means it is compression and a positive number means it is in tension.
OK, you are again correct.
 

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