Calculating Freezing Point of 50% Antifreeze Radiator Fluid

AI Thread Summary
The freezing point of a 50% antifreeze radiator fluid is being calculated, with the assumption that the other 50% is water. The molar mass of ethylene glycol is 62.07 g/mol, leading to a calculation of 8.06 mol/kg for the concentration. An initial calculation suggested a freezing point of 15°C, which was deemed incorrect. The discussion highlights the need to consider the water component in the freezing point calculation, as it significantly influences the final result. Accurate determination of the freezing point requires a proper understanding of the antifreeze-water mixture properties.
sunnyorange
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What is the freezing point of radiator fluid that is 50% antifreeze by mass? for water is 1.86 .

I used
delta: K_fc_m
First I found the molar mass of ethylene glycol to be 62.07 g/mol. Then I multiplied 1/62.06 by 500g/1 kg to get 8.06 mol/kg for cm. I plugged these values in and got 15 C. However it is incorrect. I then thought to say that -15C was the freezing point, this was also wrong.

Please help!
 
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What's the other 50% of the radiator fluid?
 
Usually water.
 
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Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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