Calculating Frequency of Siren in Windy Conditions

AI Thread Summary
The discussion focuses on calculating the frequency of a siren heard by an observer in windy conditions. The siren emits a frequency of 900 Hz, with wind blowing at 15.0 m/s and the speed of sound in calm air at 343 m/s. For the observer approaching the siren, the correct formula to use is f' = [1 + (v_o/v)]f, which accounts for the wind's effect on sound propagation. The final calculated frequencies are 941 Hz when the wind blows from the observer to the siren, and 938 Hz when it blows in the opposite direction. The calculations highlight the importance of using the correct formula and considering wind direction to determine the perceived frequency accurately.
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Homework Statement



(a) A siren emits a frequency of 900 Hz. Wind is blowing at a steady speed of 15.0 ms-1. The speed of sound in calm air is 343 ms-1. What is the frequency heard by someone approaching at 15.0 ms¹,

(i) when the wind blows from the person to the siren,
(ii) when the wind blows from the siren to the person?

Homework Equations



f'=(1+v_o/v)

The Attempt at a Solution



i figured out the relative velocity of the sound (for i 343-15) and then subbed into the formula which became 1+15/328=1.04573HZ. I'm pretty sure this isn't right because the frequency should get higher but mine inst even close... also i didnt use the given frequency at all?
 
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Check the formula.
 
That formula is the one in my textbook for the observer moving and the source stationary
 
hey, i really need some help with this if you know a different equation i should use?
 
pat666 said:
hey, i really need some help with this if you know a different equation i should use?
The correct formula is

f' = [1 + \frac{v_o}{v}]f

Velocity of sound will be depending on the direction of the wind.
 
ok thanks i don't know how i missed the second f...thanks
 
I get (i) 941Hz and (ii) 938Hz

Does this sound right?
 
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