Calculating Heart Rate from CRT Display for Beginners

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In a heart rate monitor using a CRT display, the time base is typically 0.40s/cm, which is essential for calculating heart rate. The distance between adjacent peaks on the display is 1.25cm per heartbeat. To find the time taken for one heartbeat, one must measure the distance on the screen and apply the time base. This calculation indicates that the time for 1.25cm translates to a specific duration based on the time base. Understanding these parameters is crucial for accurate heart rate measurement.
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This question is on the operation of a CRT.

In a heart rate monitor, the time base is a standard 0.40s/ms.
The distance between adjacent peaks on the display is 1.25cm per heart beat.
Calculate the time taken for one heart beat.

Any help with this will be very much appreciated. I missed a few lectures due to illness and now I'm so behind. I don't even know where to start with this!
 
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Welcome to PF.

I don't think I exactly understand your problem statement, because typically your oscilloscope will be given as time/div.

Now if you had said .40s/div then that would indicate to me that you have a .5sec peak to peak, for 1 heart beat, or 60/.5 = 120 beats per minute.
 
QueryQueen86 said:
In a heart rate monitor, the time base is a standard 0.40s/ms.
You have copied this down wrong. The timebase must be time/distance, ie 0.4s/cm

Then if you measure the distance on the screen (1.25cm) and you know how fast the trace is moving you can work out how many seconds the 1.25cm represents.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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