Calculating Heat Needed to Raise Water Temperature from 8.2◦C to 73◦C

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To calculate the heat needed to raise the temperature of 62 g of water from 8.2°C to 73°C, the specific heat formula Q=mcΔT is used, where m is mass, c is specific heat, and ΔT is the change in temperature. The calculation yields Q = (0.062 kg)(4180 J/kg·°C)(73°C - 8.2°C), resulting in approximately 16,794 J. This value can be rounded to 17 kJ or 16.8 kJ for simplicity. The solution confirms that the calculation is correct, as the provided answer of 16,794 J was accepted. Understanding the specific heat concept is crucial for solving similar problems.
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Homework Statement



This is for my physics homework and I haven't done gen chem in a while so I was wondering if this was right:

You need to raise the temperature of 62 g of water from 8.2◦C to 73◦C. How much heat is needed to accomplish this? The specific heat of water is 4180 J/kg ·◦C. Answer in units of J.

Homework Equations



Q=mc\DeltaT

The Attempt at a Solution



Q=(0.062 kg)(4180 J/kg◦C)(73◦C-8.2◦C) = 16,793.568 J

Is that right? TIA
 
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Correct approach, again problem with SD. Answering 17 kJ, or 16.8 kJ will do.
 
Thank you! I put in 16,794 and it was right.
 
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