Calculating Heat of Vaporization for Solid CO2 in Water

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To calculate the heat of vaporization for solid CO2 in water, the process involves understanding the heat transfer between the dry ice and the water. When 125 grams of dry ice is added to 500 grams of water at 66 degrees Celsius, the water cools down to 29 degrees Celsius as the dry ice sublimates. The heat lost by the water equals the heat gained by the dry ice during sublimation, forming an adiabatic system. The specific heat of water and the temperature change are crucial for determining the total heat lost by the water. Ultimately, this heat loss must equal the heat required for the sublimation of the dry ice.
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Help!---heat Of Vaporization

I could really use some help with this please!

125 grams of dry ice (solid CO2)is dropped into a beaker containg 500 grams of 66 degree celsius water. The dry ice converts directly to gas, leaving the solution. When the dry ice is gone, the final temperature of the water is 29 degrees celsius. What is the heat of vaporization of solid CO2?
 
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Homework is handled on a "you show us what you've done, and we'll point you in the direction you need to go." Take a couple wild swings --- think about the initial state (dry ice + water) and the final state, and what has happened to get from initial to final.
 
heat of vaporization

Doesn't it have to do with the Qlost=Qgain
 
I said, "...wild swing..." For a first guess, you're not doing too badly --- at the same time, very few things don't have anything to do with Ql and Qg.

You are evaporating carbon dioxide; the specific process is transition from solid phase to vapor ("sublimation" for the anal-retentive). This process requires heat, specifically, the "heat of vaporization" you used to title the thread. What do you have available as a heat source for this process in this problem?
 
Consider the dry ice and the water to comprise an adiabatic (closed with respect to heat) system, so that the loss of heat (defined in terms of calories) from the water equals the heat needed to sublimate the CO2 mass.
 
Sorry, but i am still confused about this problem.
 
ok what is Qlost & Qgain Write them in terms of mass. specific etc, Heat of sublimation etc
 
Q=mass*specific heat*change in temp.

But how does this help me?
 
Reread the problem: does it state anything about a temperature change?
 
  • #10
yes it does talk about temperature change
 
  • #11
What temperature change?
 
  • #12
The temperature change is of the fluid in the beaker which goes from 66 to 29 degrees celsius.
 
  • #13
How much heat is required for this temperature change?
 
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