Calculating height in free falling problems

  • Thread starter Thread starter akalei
  • Start date Start date
  • Tags Tags
    Falling Height
AI Thread Summary
To calculate the time taken for a stone thrown upwards to reach its maximum height, the initial speed is given as 8.0 m/s and the acceleration due to gravity is -10 m/s². The total time from launch to hitting the sea is 3.0 seconds, which includes the ascent and descent phases. The displacement equation s = ut + 1/2at² is used to find the height, but a signage error in the terms needs correction for accurate results. The final calculated height of the cliff is 69 meters. Understanding the direction of velocity and acceleration is crucial in solving free-fall problems.
akalei
Messages
2
Reaction score
0

Homework Statement


A student stands at the edge of a vertical cliff and throws a stone vertically upwards. The stone leaves the student's hand with a speed of v=8.0m/s, the acceleration of free fall is 10m/s2 and all distance measurements are taken from the point where the stone leaves the student's hand. Ignoring air resistance calculate the time taken by the stone to reach its maximum height.

The time between the stone's leaving Antionio's hand and hitting the sea is 3.0s. Determine the height of the cliff.

Homework Equations



unknown

The Attempt at a Solution


s= ut + 1/2at2
s= (8)(3) + 1/2(10)(3)2
s= 69

 
Physics news on Phys.org
If you take positive as up, then negative is down. Which way does vo (u) act? Which way does the acceleration act? Which way is the displacement of the stone to the sea? Don't forget part a.
 
i think i understand what your saying but i don't understand how to use the information to solve the problem
 
For the equation you wrote for displacement, you have a signage error in one of the terms on the right side of the equation. Can you spot it??
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top