Calculating Horizontal and Vertical Speeds of a Baseball

AI Thread Summary
The horizontal speed of the baseball remains constant at 16 m/s due to the absence of friction. The vertical speed, however, decreases over time due to gravitational acceleration, which is approximately -9.81 m/s². After 1 second, the vertical speed would be calculated as 19 m/s - 9.81 m/s, resulting in a vertical speed of about 9.19 m/s upward. The discussion emphasizes the importance of understanding projectile motion and the effects of gravity on vertical speed. Key equations related to acceleration, speed, and time are essential for solving such problems.
Crichar1
Messages
7
Reaction score
0
A baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 19 m/s upward. What are these speeds 1 s later?


horizontal speed 16 m/s
vertical speed ? m/s


I figured out that the horizontal speed would still be the same and it was. So i thought that the vertical speed 1 s later would be double that, so 38 m/s but that was incorrect also.
 
Physics news on Phys.org
This problem assumes no friction, and that is why the horizontal speed is constant.

Think about your answer for the vertical speed. What happens when you throw an object straight into the air? According to your answer, it picks up more and more speed and never comes back down. =) The baseball must continually slow down until it reaches the highest point of its trajectory, where it then stops (the vertical motion stops, not the horizontal motion though), and it then picks up vertical speed as it falls back to the earth. Do you have any equations that describe such motion relative to time?
 
Hi Crichar1! :smile:
Crichar1 said:
A baseball is hit with a horizontal speed of 16 m/s and a vertical speed of 19 m/s upward. What are these speeds 1 s later?.

How much is the acceleration (including the units)?

What equation connects acceleration speed and time? :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top