Calculating Impulse and Force: Physics Homework Help

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The discussion focuses on calculating the impulse and average force exerted by a baseball on a catcher. The impulse is calculated as the product of mass and velocity, resulting in -4.93 kg m/s, indicating the force acts in the opposite direction of the ball's motion. The average force is then derived from the impulse divided by the time of contact, yielding 214 N. There is a clarification regarding the interpretation of the force's direction, suggesting that the force delivered by the ball should be considered positive if the initial velocity is positive. The calculations emphasize the relationship between momentum, impulse, and force in physics.
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A catcher catches a 145g baseball traveling horizontally at 34.0 m/s

1. How large an impulse does the ball give to the catcher?
2. If it takes the ball 23.0ms to stop once it is in contact with the catcher's glove, what average force did the ball exert on the catcher?


is this right...

1. .145 kg x 34.0 m/s = –4.93 kg m/s (the minus sign indicates the force acts in the opposite direction of the baseball's velocity).

2. The impulse I = F x t and F = I / t = –4.93 kg m/s / 0.0230 s = 214 kg m/s^2 = 214 N
 
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Aren't 1) and 2) asking about what the ball delivers? Won't the force of the ball delivers be positive if V is in the positive direction?
 
Momentum is mass x velocity, while the force = rate of change of momentum; i.e. d(mv)/dt.
 
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