Calculating Impulse and Mass of a Basketball

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The impulse on the basketball is calculated as 1 N·s, derived from the force of 10 N exerted over 0.1 seconds. To find the mass of the basketball, the change in momentum (delta p) is used, but the change in velocity (delta v) needs to be determined first. The velocity just before impact when dropped from a height of 2 m can be calculated using the equation for free fall, yielding approximately 6.26 m/s. Assuming an elastic collision, the speed of the ball upon bouncing back is equal to the speed just before impact. Thus, the mass can be calculated using the impulse and the determined velocity.
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Homework Statement


A playerbounces a basketball on the ground. If the ground exerts a force F = 10N on the ball in 0.1 seconds, what is the impulse on the basketball. If the ball is simply dropped from a height of 2m, assuming the impulse to be the same as before, what is the basketball's mass?


Homework Equations



impulse= delta p = m delta v = F delta t

The Attempt at a Solution


For the impulse I have 10N x 0.1 seconds which = 1 N s

For the mass of the basketball I tried m = delta p/delta v

So delta p is the impulse 1 N x s but I don't know how to find delta v
 
Last edited:
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The ball is dropped from a height of 2 m. Can you find v just before it impacts the floor?

It sounds like we should assume the collision is elastic, i.e. the speed of the ball leaving the floor is the same as the speed just before impact.
 

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