Calculating Impulse of a Collision: A Simple Guide

  • Thread starter Thread starter bengaltiger14
  • Start date Start date
AI Thread Summary
To calculate the impulse of a collision, the equation used is Impulse = Force x Time. Given an average force of 509.79 N and a collision time of 35.1 milliseconds, the impulse can be calculated directly in Newton-seconds. There is confusion regarding the desired unit of Joules-seconds, as impulse is typically expressed in Newton-seconds, which is equivalent to momentum. The discussion suggests that the request for Joules-seconds may be a typo. Ultimately, the correct calculation should yield the impulse in Newton-seconds.
bengaltiger14
Messages
135
Reaction score
0
I was to calculate the impulse of a collision. I was given the Average force in Newton, and the collison time in seconds. I need the answer to be in Joules - Seconds and not in Newton - Seconds. I used the equation Impulse = Force x Time. I am have a tremendous brain fart. Can you help?
 
Physics news on Phys.org
I don't think you want your answer to be in Joule-seconds, since that's not the unit of momentum...

What's the context?
 
A collision occurs w/ a time of impact is 35.1 milliseconds and the average force is 509.79 N. What is the impulse (in Joules-Seconds)?
 
I would just go with F*t and ignore that part. It may just be a typo
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top