Calculating Induced EMF from AM Radio Broadcast and Dipole Antenna

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The discussion focuses on calculating the induced electromotive force (emf) in a dipole antenna from an AM radio broadcast. The average power of the broadcast is 4.00 kW, and the dipole antenna is 65.0 cm long, located 4.00 miles from the transmitter. The maximum electric field (Emax) was calculated to be 0.0058 V/m, leading to a maximum magnetic field (Bmax) of 1.9305 x 10^-11 T. To find the induced emf, the relationship between Emax and the antenna length is emphasized, suggesting conversion of Emax to V/cm for compatibility with the antenna length. The final calculation of the induced emf requires applying the appropriate formula using these values.
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Homework Statement


An AM Radio station broadcasts isotropically(equally in all directions) with an average power of 4.00kW. A dipole receiving antenna 65.0cm long is at a location 4.00 mi from the transmitter. Compute the amplitude of the emf that is induced by this signal between the ends of the receiving antenna.


Homework Equations


P_{avg}=S_{}avgA
E_{max}=\sqrt{\mu_{\circ}cP_{avg}/2\pir^2}
B_{max}=\frac{E_{max}}{C}

The Attempt at a Solution


Used the avg power to find the E_{max} to be .0058V/M. tHen used this to find the B_{max} to be 1.9305*10^-11T. I am not sure how to calculate the emf from this.
 
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Use the fact that the antenna is 65.0 cm long, and the value of Emax that you found.
 
what equation would I use those in?
 
Here's a hint: the units on Emax are V/m ... which could also be converted to V/cm if you like. You have the length in cm, as well as the number of Volts per cm ... so how many Volts?
 

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