Calculating Induced EMF in a Solenoid Inductor

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To calculate the induced EMF in the solenoid inductor, the relevant equation is emf = -L (ΔI/Δt), where L is the inductance and ΔI/Δt is the rate of change of current. Given the solenoid's inductance of 85 mH and a current decrease of 2.5 A/s, the induced EMF can be calculated directly. The user is uncertain about the application of the formula and whether to include mutual inductance or other factors. The discussion highlights the need for clarity on using the correct variables and equations to find the induced EMF accurately. The final induced EMF will be one of the provided options based on the calculations.
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Homework Statement



An 85 mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil resistance is 8.1 ohms. The mutual inductance of the coil and solenoid is 27 µH. At a given instant, the current in the solenoid is 540 mA, and is decreasing at the rate of 2.5 A/s. At the given instant, the induced emf in the solenoid is closest to:
A) 170 mV
B) 150 mV
C) 210 mV
D) 230 mV
E) 190 mV

Homework Equations



emf =-N (ΔΦ/Δt)

The Attempt at a Solution



i've tried to think of other equations to use such as ωBA sin θ where it would be 90 degrees because that's the peak. but that doesn't work.
so i though i might be able to use the above equation but it seems like i am missing too many variables.
i know the equation for self inductance is ( -L * ΔI/Δt )
but it is in the given instant and not over a range of time..
any small guidance would be much appreciated; I'm not sure where to go from here.
 
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would i just go about it by perhaps multiplying the 85 mH of the sole by the rate of decrease which is 2.5 A/s?
 
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