Calculating Inertia and Kinetic Energy of Connected Shafts

AI Thread Summary
The discussion focuses on calculating the moment of inertia, final speed, angular torque, and kinetic energy of two connected shafts operating in opposite directions. Shaft 1 has a moment of inertia of 4.62 kgm², while Shaft 2 has 12.17 kgm². When connected, the final speed of the shafts is determined to be 57.9 rad/s, equivalent to approximately 552.9 rev/min. The angular torque developed when the rotational speed increases to 900 rev/min over 3.2 seconds is a key point of confusion, with clarification needed on whether to consider the combined speed or just Shaft 1. The calculations for kinetic energy at the increased speed follow once the torque issue is resolved.
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Homework Statement



b) During the operation of a machine, two shafts rotate in opposite directions and are then connected by a clutch system. Shaft 1 has a rotational speed of 800 rev/min, a mass of 35 kg and a radius of gyration of 375 mm. Shaft 2 has a rotational speed of 1100 rev/min, a mass of 45 kg and a radius of gyration of 520 mm. Determine:

i) the moment of inertia for each shaft;
ii) the final speed and direction of rotation for the connected shafts;
iii) the angular torque developed by the connected shafts if the rotational speed increases to 900 rev/min in a time of 3.2 s.
iv) the kinetic energy of the connected shafts at the increased speed.

Homework Equations



I1=m1k1squared
w3= 2pieN/60


The Attempt at a Solution



i. calculate I(1)=m1k1squared answers were 4.62 kgm2 & 12.17 kgm2
ii anti clockwise 57.9 rad/s with N3 working out 552.9 rev/min

iii not sure what changes speed here is it full speed combined or just shaft 1 ? Think I know how to do the rest when this is solved
 
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username0194 said:
is it full speed combined or just shaft 1 ?=
It says 'connected', so I would take it as the two shafts combined.
 
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