Calculating Integrals with Cauchy Formula

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SUMMARY

The forum discussion focuses on calculating integrals using the Cauchy Integral Formula, specifically evaluating the integral \(\int\limits_C\frac{e^{2z}}{z^2-4}\mbox{d}z\) where the closed curve \(C\) encloses the point \(z=2\). The solution involves rewriting the integrand as \(\frac{e^{2z}}{(z-2)(z+2)}\) and applying the formula, resulting in the evaluation of the integral to be \(\frac{1}{2}\pi e^4 i\). The correctness of the solution is affirmed, including cases where \(C\) is an ellipse.

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Homework Statement


using cauchy integral formula calculate
\int\limits_C\frac{e^{2z}}{z^2-4}\mbox{d}z
where C is closed curve (point z=2 is inside)

The Attempt at a Solution


\ldots=\int\limits_C\frac{e^{2z}}{(z-2)(z+2)}\mbox{d}z=\int\limits_C\frac{f(z)}{z-2}\mbox{d}z=2\pi if(2)=2\pi i\frac{e^{2\cdot2}}{4}=\frac12\pi e^4i
is it correct?
 
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Yes, and yes for the other one where C is an ellipse.
 

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