Calculating Jump Landing Position

  • Thread starter Thread starter Bozzy
  • Start date Start date
  • Tags Tags
    Jump Position
AI Thread Summary
To calculate the landing position of a jumper in 3D space, consider the effects of gravity and initial speed. The total time in the air can be determined using the equation T = 2*sqrt(2h/g), where h is the jump height and g is the acceleration due to gravity. This time is then used to calculate the horizontal distance traveled using the equation r = 2v*sqrt(2h/g), where v is the initial velocity. The calculations assume minimal air resistance, allowing for straightforward application of physics principles. Understanding these equations will help in accurately determining the landing position.
Bozzy
Messages
2
Reaction score
0
Hi,

I need a bit of help with the following:

I need to calculate the landing position of a man if he jumped, using his speed, gravity and jump height. This needs to be done in 3D-space.

I would use the template, but I really don't know where to start. I imagine it's something to do with momentum and such, but I'm really struggling to grasp what I need to do.

Any sort of help at all would be great!

Thanks,
Rich
 
Physics news on Phys.org
Why do you need to do it in 3D space for? Is there an associated diagram with the man jumping in (x,y,z) coordinates?
 
Assuming drag force from air is minimal to 0, the time it takes for an object to fall is independent of its speed along the x or z axis (w/o air a bullet and a dropped ball will fall with the same speed.)
Therefore, using his jump height, his initial speed along the y-axis and some basic equations, you can figure out how long he'll be in the air. Therefore, by knowing time (t), and the velocities in the x and z direction determine how far he'll go in each direction.

The problem may be more complex and beyond me (i've only taken AP physics), but i hope this helps.
 
Hi,

Well, that sounds like it's what I want... Can you write the equation I would need? It's easier for me to grasp stuff from equations!

Cheers,
Rich
 
Well the easiest way to do this is to realize that without air resistance or anything interfering with his jump that the total time of the jump is equal to twice the time it would take him to fall from that height. It takes the same time to go up as it does to come down in this case.

So we simply calculate the free-fall time from a height 'h' and multiply it by two giving:
T = 2*sqrt(2h/g)
where T is the total time he spends in the air (including going up), and g is the positive acceleration due to gravity.

The rest is easy since we now know the time simply use the equation v = d/t
and you can see that the position (assuming he lands at a place level with his original surface) is directly in front of him a distance of 'r' :
r = 2v*sqrt(2h/g)
v is his velocity before jumping.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top