Calculating KE of Slowest Emitted Photoelectron

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To calculate the kinetic energy (KE) of the slowest emitted photoelectron, one must consider the photoelectric effect, where the energy of the incoming photon (hf) equals the work function of the metal. When the photon energy matches the work function, the emitted electron has zero kinetic energy, resulting in a velocity of zero. Thus, the slowest emitted photoelectron is characterized by having no kinetic energy, as it does not possess enough energy to overcome the work function. This means that the lowest possible KE is indeed zero, which corresponds to a stationary electron. Understanding this concept is crucial for accurately interpreting photoelectron emission in experiments.
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how do you calculate the kintetic energy of the slowest emitted photoelectron? i know how to calculate the KE of the fastest emitted photoelectron.
 
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?Not sure I get this

Surely there is a spectra of ke from 0 - ke.max, so the lowest possible ke = 0 which gives v=0?

- does v=0 count as slow or stopped?

What exactly is the wording of the question?
 
I assume you're talking about the photoelectric effect. The slowest emitted photoelectron is emitted with speed zero.
 
hf=work function of metal + 1/2mv2...slowest emitted electron would be when hf=work function metal so leaving zero kinetic energy for emitted electrons resulting in 0 velocity.
 
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