Calculating Ksp for M2X3: Solubility and Equilibrium Calculation

  • Thread starter Thread starter Soaring Crane
  • Start date Start date
  • Tags Tags
    Ksp
AI Thread Summary
The solubility of M2X3 in water at 298K is 4.12 x 10^-4 M, leading to the dissociation equation M2X3 <--> 2M3+ + 3X2-. The molarity of M3+ is calculated as 8.24 x 10^-4 M, while the molarity of X2- is 1.236 x 10^-3 M. The solubility product constant (Ksp) is determined using the formula K_sp = [M3+]^2*[X2-]^3. The final calculated value for Ksp is 1.28 x 10^-15.
Soaring Crane
Messages
461
Reaction score
0
The solubility of M2X3 (as M3+ and X2-) in water at 298K is 4.12 x 10-4 M. Calculate Ksp for M2X3.

M2X3 <--> 2M3+ + 3X2-

K_sp = [M3+]^2*[X2-]^3

Now Molarity of M3+ = (4.12 x 10-4) M2X3*(2 mol M3+/1 mol M2X3) = 8.24E-4 mol = Molarity

Molarity X2- = (4.12 x 10-4) M2X3*(3 mol X2-/1 mol M2X3) = 1.236E-3 mol = molarity

K_sp = [8.24E-4 M]^2*[1.236E-3]^3 = 1.28E-15

Thanks.
 
Physics news on Phys.org
OK
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...

Similar threads

Replies
3
Views
4K
Replies
14
Views
11K
Replies
1
Views
3K
Replies
13
Views
4K
Replies
2
Views
10K
Replies
1
Views
4K
Replies
1
Views
3K
Back
Top