Calculating Length of Wire in a Generator Coil with Given Parameters

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To calculate the length of wire in a generator coil with 100 turns, a 0.50-T magnetic field, and an rms emf of 120 V at 60 Hz, the correct approach involves using the equation E = NABw(1/sqrt(2)) to find the area A. After determining the angular frequency w as 377 rad/s, the area is calculated to be approximately 0.009 m², leading to a side length of the square coil of about 0.095 m. The total length of the wire is found by calculating the perimeter of the square and multiplying by the number of turns, resulting in a final length of 38 m, which matches the book's answer. The confusion arose from initially including the sin(wt) term and miscalculating the area based on the shape of the coil. The discussion emphasizes the importance of correctly applying formulas for generator problems.
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Homework Statement



A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf has an rms value of 120 V. Assuming that each turn of the coil is a square (an approximation), determine the length of the wire from which the coil is made.

Homework Equations



Emf = NABwsin(wt) -- not sure if i should utilize sin(wt)?

and w = 2(pi)f

The Attempt at a Solution



I notice that the problem includes emf as an rms value. I figure that it is sq(2). Then, I figure out the w - the value is 377.

The problem setup so far is...

sq(2)*120V = (100 turns)(A)(0.50-T)(377) sin (377*.02) ---- i figured time, t by using the frequency T = 1/f equation.

Solving for A, I get A = .069 m^2. I then solve for the radius using A = (pi)r^2 and get r = .148 m. Then, I plug the r into L = 2(pi)r to get length. My answer is L = .931 m (final answer).


Book Answer: 38 m

Now the answer I was given doesn't match with what i was given. I am guessing whether I should multiply by 100 since there are that many turns in the coil? Or just ignore the sin(wt) part? I just don't know how to fix this problem. My book does a horrible job explaining how to approach generator problems.
 
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cheechnchong said:

Homework Equations



Emf = NABwsin(wt) -- not sure if i should utilize sin(wt)?
That equation will give you the instantaneous Emf--but you need the RMS value. Big hint: Replace sin(wt) by 1/sq(2).

The problem setup so far is...

sq(2)*120V = (100 turns)(A)(0.50-T)(377) sin (377*.02) ---- i figured time, t by using the frequency T = 1/f equation.
Get rid of that sin(wt) term and your value for time.

Solving for A, I get A = .069 m^2. I then solve for the radius using A = (pi)r^2 and get r = .148 m. Then, I plug the r into L = 2(pi)r to get length. My answer is L = .931 m (final answer).
It's a square, not a circle.

Now the answer I was given doesn't match with what i was given. I am guessing whether I should multiply by 100 since there are that many turns in the coil?
Of course--you want the total length of the wire.

Or just ignore the sin(wt) part? I just don't know how to fix this problem.
See my comments above.
 
I used the equation E = NABw(1/sq(2)). I solved for w using w = 2(pi)f. Plugged all the values into the equation and got A = .009 m^2.

This is where I'm stuck...After solving for the side of the square A = s^2 using .009 m^2 (area that was figured), I came up with s = .095 m. How can I figure the L-value? I'm STUCK here!

What's the fix there doc?
 
What's the circumference of a square? How many squares do you have?
 
Doc Al said:
What's the circumference of a square? How many squares do you have?

Doc Al, you are awesome! worked out just fine...
 
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