Calculating load for tidal movement

AI Thread Summary
Calculating tidal movement load involves using wind load formulas, specifically wind speed squared multiplied by 0.00431 and the area in square feet. For example, a 5 mph wind on a 100 sq. ft. surface results in a force of 10.77 lbs. The mass of salt water being approximately 854 times that of air raises questions about adapting wind load calculations for water. Different atmospheric conditions may also influence the weight of water, necessitating adjustments in calculations. Various standards and coefficients, such as those in API 2SK, are essential for accurate force assessments on ocean vessels.
jamesd442001
Messages
3
Reaction score
0
Calculating wind load is wind speed squared x .00431 x area in sq. ft. A 5 mph wind with a vertical 100 sq. ft. wing is 10.77 lbs. The mass of salt water is around 854 times greater than the mass of air. Can you use the wind formula and multiply by 854? Does the weight of water at different atmospheres change this?
 
Engineering news on Phys.org
jamesd442001 said:
Calculating wind load is wind speed squared x .00431 x area in sq. ft. A 5 mph wind with a vertical 100 sq. ft. wing is 10.77 lbs. The mass of salt water is around 854 times greater than the mass of air. Can you use the wind formula and multiply by 854? Does the weight of water at different atmospheres change this?

What is the context of this question? Various standards would apply and have things such as shape coefficients that will change the resultant force from environmental loadings.

The type of hull (presumably this is for an ocean vessel) may also introduce other factors to consider.

That being said, the final calculation will be some derivative of the basic equation:

F = PA

API 2SK is a good reference for this. For a ship hull the current force on the bow or stern (in lbf) is:

F_{cy} = C_{cy}SV_c^2

where,

S = wetted surface area of hull including appendages (ft^2)
V_c = current speed (knots)
C_cy = current force coefficient = 0.40 lbf/(ft^2 - knots)

Hope this helps.

CS
 
Thread 'I need a concave mirror with a focal length length of 150 feet?'
I need to cut down a 3 year old dead tree from top down so tree causes no damage with small pieces falling. I need a mirror with a focal length of 150 ft. 12" diameter to 36" diameter will work good but I can't think of any easy way to build it. Nothing like this for sale on Ebay. I have a 30" Fresnel lens that I use to burn stumps it works great. Tree service wants $2000.
Hi all, i have some questions about the tesla turbine: is a tesla turbine more efficient than a steam engine or a stirling engine ? about the discs of the tesla turbine warping because of the high speed rotations; does running the engine on a lower speed solve that or will the discs warp anyway after time ? what is the difference in efficiency between the tesla turbine running at high speed and running it at a lower speed ( as fast as possible but low enough to not warp de discs) and: i...
Thread 'Where is my curb stop?'
My water meter is submerged under water for about 95% of the year. Today I took a photograph of the inside of my water meter box because today is one of the rare days that my water meter is not submerged in water. Here is the photograph that I took of my water meter with the cover on: Here is a photograph I took of my water meter with the cover off: I edited the photograph to draw a red circle around a knob on my water meter. Is that knob that I drew a red circle around my meter...
Back
Top