Calculating lost mechanical energy

AI Thread Summary
To calculate the lost mechanical energy in the collision between the two football players, first determine the total mechanical energy before the collision by adding the kinetic energies of both players. After the collision, calculate the mechanical energy of the combined mass using the velocity obtained from the previous problem. The difference between the total mechanical energy before and after the collision represents the lost mechanical energy. It's important to note that since this is an inelastic collision, some energy is indeed lost, primarily converted into other forms such as heat and sound. Understanding this concept is crucial for accurately solving the problem.
bona0002
Messages
14
Reaction score
0
Hey guys,

I'm trying to complete a homework problem, but I'm not quite sure how to approach it. Here is the question: A 90.5-kg fullback running east with a speed of 4.91 m/s is tackled by a 94.7-kg opponent running north with a speed of 2.93 m/s. Determine the mechanical energy that disappears as a result of the collision.

This question actually came after the question that read: Calculate the velocity of the players immediately after the tackle.

I solved that problem with the value of the magnitude being 2.83 m/s and the value of θ = 32.0°.

Now I know that in the book, they say that E_mech = K + U (kinetic energy and potential energy), but I don't quite know how to calculate the lost mechanical energy. Any pointers of how the process would go would be appreciated!

Thanks!
 
Physics news on Phys.org
Now I know that in the book, they say that E_mech = K + U (kinetic energy and potential energy), but I don't quite know how to calculate the lost mechanical energy. Any pointers of how the process would go would be appreciated!

Just calculate the mechanical energy before and after, then compare them.
 
I understand how to calculate the mechanical energy after the collision, but how do I do it before? Do I calculate the mechanical energy of the runner, of the tackler, or do I add both their mechanical energies prior to the collision, and then compare?
 
Ok, just tried it by adding the two mechanical energies prior to the collision and that gave me the correct answer. Thanks for the help!
 
bona0002 said:
Ok, just tried it by adding the two mechanical energies prior to the collision and that gave me the correct answer. Thanks for the help!


So is there any loss in the mechanical energy? I can't think of a reason for loss :S
To me it seems like both momentum and energy is conserved?
 
timarli said:
So is there any loss in the mechanical energy? I can't think of a reason for loss :S
To me it seems like both momentum and energy is conserved?
It's an inelastic collision. The two masses coalesce. Energy will certainly be lost.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top