Calculating Magnetic Field of a Solenoid with Changing Amperage

AI Thread Summary
To calculate the magnetic field of a solenoid with changing amperage, the key equations involve B = μ*N/l*I and the flux Φ. The user is focused on the rate of change of current (dI/dt) and needs to incorporate this into their calculations. They seek clarification on how to handle amperage expressed in amps per second when calculating the derivative of flux over time. The discussion emphasizes that differentiation and integration can be interchanged due to their linear nature, and suggests finding dB/dt from the initial magnetic field expression. Understanding these concepts will help in accurately determining the magnetic field's behavior as the current changes.
GermanMC
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Homework Statement


I've been given a solenoid and I have N/l = 100 turns/meter, dI/dt = 0.05A/s and a radius of 0.005m. I am only concerned with the dI/dt.


Homework Equations



B = μ*N/l*I
\Phi = \int\int B\bulletn dl
\epsilon = d\Phi/dt

The Attempt at a Solution



For B I get the field but how do I deal with my amperage in amps/s instead of just amps. Once I get that I'll take the derivative of the flux with respect to time and I'll be fine. Any clues will be much appreciated.
 
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When you take d(phi)/dt of your 2nd expression, you can interchange the order of differentiation and integration because both are linear operations. d/dt comes inside and operates on B. You find dB/dt from your first expression, which looks wrong BTW. (Shouldn't I be in the denominator?)
 
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