Calculating Magnetic Field of a Tight Coil

AI Thread Summary
To calculate the magnetic field at the center of a tight coil made from a 1.88 m long wire carrying a current of 3.1 A, Ampere's law is typically applied. The user expressed difficulty in setting up the equation correctly and requested a complete solution for comparison. Forum participants emphasized the importance of showing the work done to facilitate assistance rather than simply providing answers. The discussion was moved to the Intro Physics category for better context. Accurate calculations and proper equation setup are crucial for determining the magnetic field in this scenario.
lemaire
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Homework Statement




A 1.88 m long wire carrying 3.1 A is wound into a tight, loop shaped coil 0.05 cm in diameter. What is the magnetic field at its center?

Homework Equations





The Attempt at a Solution


I use Ampere's law but i get the wrong answer. I think i did not set up the equation right. Please i need answer with equation so i can compare it to mine not a chat.
Thank you for your comprehension.
 
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Post the work that you did, and then we can try to help you. We do not give out answers here on the PF (check the Rules link at the top of the page).

What equations are you using? I'm also moving this thread to Intro Physics.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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