Calculating Magnetic Field Strength for Parallel-Plate Capacitor

AI Thread Summary
To calculate the magnetic field strength at a distance from the axis of a parallel-plate capacitor, the relevant equation involves the permeability of free space and the rate of change of charge. The user initially calculated a value of 2.4 but realized unit conversion for the electric field's rate of change is necessary. They also considered the charge of an electron in their calculations. A reference value from masteringphysics.com provided a magnetic field strength of 1.67*10^-13 T. The discussion then shifted to calculating the magnetic field strength at 7 cm from the axis.
spacemanrussell
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Homework Statement


A 10-cm-diameter parallel-plate capacitor has a 1.0 mm spacing. The electric field between the plates is increasing at the rate 1*10^6V/m/s.

What is the magnetic field strength 3.0 cm from the axis?



Homework Equations


B= uo/(2*pi) *r/R^2*(Chang in Q/ change in time)


The Attempt at a Solution



I keep getting 2.4
 
Physics news on Phys.org
I think you need to change the unites for the increase rate to C/s.
anyone knows how?
 
Oh good thinking- I probably need to accound for the charge of an electron.
 
I got the answer from masteringphysics.com 1.67*10^-13 T.
Now what is the magnetic field strength 7cm from the axis?
 

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