Calculating Magnetic Flux from a Solenoid with Given Parameters

AI Thread Summary
A solenoid with a diameter of 2.50 cm, length of 26.0 cm, 285 turns, and carrying 12.0 A is analyzed for magnetic flux calculations. For part (a), the magnetic field inside the solenoid is calculated using the formula B=μ₀*n*I/L, leading to a value of 0.01653 T. The magnetic flux through a disk of radius 5.00 cm is then determined using the correct radius of 1.25 cm, resulting in the correct answer. The discussion highlights a misunderstanding regarding the magnetic field outside the solenoid and a typo in the textbook. The participant ultimately resolves their confusion and confirms their calculations.
Slimmy
Messages
10
Reaction score
0

Homework Statement


A solenoid 2.50 cm in diameter and 26.0 cm long has 285 turns and carries 12.0 A.
p30-34.gif

(a) Calculate the flux through the surface of a disk of radius 5.00 cm that is positioned perpendicular to and centered on the axis of the solenoid, as in Figure P30.36a.
(b) Figure P30.36b shows an enlarged end view of the same solenoid. Calculate the flux through the blue area, which is defined by an annulus that has an inner radius of 0.400 cm and outer radius of 0.800 cm.

Homework Equations


Unless it wants me to use the law of Biot-Savart...I believe for a solenoid, the magnetic field is:
B=mu_0(n)L
and
Magnetic Flux =
[Surface integral](B (dot) dA)

The Attempt at a Solution


Well, for part (a) my book states for a very long solenoid, there is no magnetic field outside of it, but I believe that is for an infinite solenoid? But in any case, I found the magnetic field assuming it was a long solenoid, then once I did that, the only part of the circle that would be in a magnetic field would be the part that is in the solenoid, so the radius is 1.25cm for the area in the magnetic flux equation, but this outlook is incorrect. For part (b)..I was too discouraged to work towards it.
 
Last edited by a moderator:
Physics news on Phys.org
Could you please show your work for (a) so we can see where you went wrong, thanks.
 
Oh, the reason I did not show my work, is because I believed that my whole concept was incorrect...I am allowed to assume this as a very long Solenoid? One second, let me get my work real quick.

Alright, so I have the equation...

B=mu_0*n*I*1/L
and I find the magnetic field to be
.01653 T

Then I find the area that is being affected from the solenoid, and that is technically the diameter of the solenoid, so
diameter=2.5E-2 M
Radius=1.25E-2 M
Magnetic Flux = .01653*pi*(1.25E-2)^2...
And that gave me the right answer...

I know what I was doing wrong, the book had a typo saying the magnetic field was: B=mu_0*n*L
Sorry to bother you.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top