Calculating Marble's Initial Height Using Projectile Motion Equations

AI Thread Summary
To determine the initial height from which the marble was thrown, the projectile motion equation delta y = (V0^2 sin^2 theta)/(2g) is used. The marble is thrown horizontally at 10 m/s and strikes the ground at an angle of 68°. Initial calculations suggested heights of 4.39 m and 421.24 m, but both were incorrect. Further assistance is needed to review the complete calculations to identify errors. Accurate calculations are essential for solving the problem effectively.
IAmSparticus
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Homework Statement


A marble is thrown horizontally with a speed of 10 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle 68° with the horizontal. From what height above the ground was the marble thrown?



Homework Equations


delta y = (V02 sin2 theta)/(2g)


The Attempt at a Solution


4.39 m and 421.24. Neither correct.
 
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Hi IAmSparticus! :wink:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help! :smile:
 

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