Calculating Mass of Stars in a Binary System

AI Thread Summary
In a binary star system with two equal-mass stars separated by 340 million kilometers, the calculation of each star's mass involves using the orbital period of 5 Earth years. The initial formula presented for mass calculation was incorrect due to a misunderstanding of the radius, which should be the full distance between the stars rather than half. The correct approach involves using the semi-major axis as the radius in the formula, leading to a revised calculation. The confusion arose from interpreting the distance and orbital mechanics, emphasizing the need to treat one star as stationary while the other orbits. Ultimately, understanding the correct application of the gravitational force and distance is crucial for accurate mass determination.
chazgurl4life
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Q:
Suppose that a binary star system consists of two stars of equal mass. They are observed to be separated by 340 million kilometers and take 5.0 Earth years to orbit about a point midway between them. What is the mass of each?
I figured out that:
mass=4pi^2(radius)^2/Gravitational Force(#of years)*(distance)2
m= [4(3.14)^2(3.3x10^29)^3]/[(6.67x10^-11){(8.0 years)(3.4x10^7}^2] =3.33x10^29 then (3.33x10^29)/2 = 1.7x10^29

I don't know what I'm doing wrong here. Any ideas?
 
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chazgurl4life said:
Q:
mass=4pi^2(radius)^2/Gravitational Force(#of years)*(distance)2

Maybe an algebra mistake in getting to this point. Should be:
mass=4pi^2(radius)^3/(Gravitational Force(#of years*seconds per year)^2)

How did you know your answer was wrong? It's very close to correct. Does the back of the book give the answer?
 
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so if i reply this equation it comes out as:
m=4pi^2(3.3x10^29)^3/6.67e-11(5yearsx 3.155815296E7 sec per yr)^2

is that right? or am i using the wrong radius? isn't the radius half the distance between the two stars? if that's true than the radius id 170 million, isn't it? I am so confused!
 
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Where did you get 3.3 x 10^29. They give you the distance of 340,000,000 million kilometers. This becomes your a or radius (3.4 x 10^11 meters)

It's not half the distance between the 2 stars since. Pretend 1 star is still, and the other orbits it. It will trace an orbit whose diameter is twice the distance between the 2 stars. Therefore, the distance between the 2 stars becomes the radius, or semi-major axis in this problem.
 
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