Calculating Maximum Force Acting on 28kg Mass: F=ma

AI Thread Summary
To calculate the maximum force acting on a 28 kg mass described by the position function x(t) = 3.0sin(15.0t), the maximum value of the sine function, which is 1, is crucial. The acceleration can be derived by taking the second derivative of x(t), leading to the equation a(t) = -3.0 * 15.0^2 * sin(15.0t). The maximum acceleration occurs when sin(15.0t) equals 1, resulting in a maximum acceleration of 675 m/s². Using F=ma, the maximum force can then be calculated as F = 28 kg * 675 m/s², yielding a maximum force of 18,900 N. Understanding the relationship between the sine function's maximum value and the time variable is essential for accurate calculations.
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The position of a mass m = 28.0 kg is given in by x(t) = 3.0sin ((15.0)t). Calculate the magnitude of the maximum force acting on the mass.

F=ma. I tried deriving x(t) twice to get the acceleration equation so i could plug it into F=ma and then pick a random number for t. I chose t=1 but i still didn't get the right answer.
 
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Hint: the maximum value of sin(kt) or cos(kt) is 1 where k is any constant.
 
So I guessed correctly with t=1. But I'm still stumped on where to go from there. Do I still take the 2nd derivative of x(t)?
 
You are confusing the maximum value of sin(kt) with the value of t.

If k = 1, is sin (1) a a maximum? Sin (x) and Cos (x) both have maximum values of 1, but the x values where this occurs are different.
 
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