Chemistry Calculating Moles of Chlorine Atoms in 71g of MCl2

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To calculate the moles of chlorine atoms in 71g of MCl2, first determine the number of moles of MCl2 using its molar mass of 70.9 g/mol, which results in approximately 1.00 mol of MCl2. Since each molecule of MCl2 contains two chlorine atoms, the total moles of chlorine atoms is double that amount, yielding 2.00 moles of chlorine. The atomic weight of chlorine is approximately 35.5 g/mol, which supports the calculations. Thus, the final answer is 2.00 moles of chlorine atoms in 71g of MCl2.
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Homework Statement


How many moles of chlorine atoms are there in 71g?

Given:
mCl2=71g
nCl2=1.00 mol
MCl2=70.9g/mol

Homework Equations



?

3. The Attempt at a Solution

Not sure how to go about this question.

Would it just be n multiplied by 2?
 
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Sace Ver said:

Homework Statement


How many moles of chlorine atoms are there in 71g?

Given:
mCl2=71g
nCl2=1.00 mol
MCl2=70.9g/mol

Homework Equations



?

3. The Attempt at a Solution

Not sure how to go about this question.

Would it just be n multiplied by 2?
Yes. The question asks for how many moles of chlorine atoms there are in 71 g. The atomic weight of one chlorine atom is approx. 35.5

https://en.wikipedia.org/wiki/Chlorine
 
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