Calculating Moment of Inertia for the Falling Mass Method

AI Thread Summary
To calculate the moment of inertia of a wheel using the falling mass method, one must first determine the acceleration of the falling mass through time and distance measurements. The relationship between the rotational inertia of the wheel and the acceleration can be established using Newton's second law for both the wheel and the falling mass. The torque can be calculated as the force acting on the wire multiplied by the radius of the shaft. With the torque and angular acceleration known, the moment of inertia can be derived using the equation τ = Iα. This method effectively allows for the determination of the wheel's rotational inertia.
willwoll100
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Could anyone help me calculate the moment of inertia of a wheel by the falling mass method, the data I've got is below,

Distance mass falls

Time taken

Mass fallen

Radius of shaft that the wire wraps around which is attached to the mass

Is is just the mass*radius^2? It just doesn't seem right?

Thanks
 
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I assume you have a light cable wrapped around the wheel shaft with a mass at the end. Then you let the mass fall from rest? And that the purpose of the experiment is to determine the rotational inertia of the wheel?

Given the acceleration of the falling mass you can figure out the rotational inertia of the wheel. You can figure out the acceleration from measurements of the time and distance (using kinematics).

To see how the rotational inertia relates to the acceleration of the falling mass, apply Newton's 2nd law to the wheel and to the falling mass.
 
Yes the wire is deemed of no mass and the mass added falls from rest, I've calculated the acceleration which is constant due to the force applied never changing which is 2*S/t^2, I've also calculated the angular acceleration which is acceleration/radius in rad/s^2. Force P acting in the wire is m(9.81-a) I have also calculated as well the torque Which is P*radius of shaft.
 
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If you've calculated the torque and the angular acceleration, you have all you need to find the rotational inertia: \tau = I \alpha.
 
I thought of that but was unsure whether I could use that equation for this problem, thanks for your help :biggrin:
 
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