Calculating Monarch Butterfly Flight Time in Steady Wind Conditions

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Monarch butterflies migrate at a speed of 4.4 m/s, and with a steady 2.4 m/s breeze from the east, their effective speed traveling west increases to 6.8 m/s. To cover a distance of 4.7 km, the outbound trip will take approximately 690 seconds, while the return trip against the wind will take longer at around 1,000 seconds. The total round trip time, factoring in the wind, is about 1,690 seconds. If there were no wind, the round trip time would be significantly shorter, calculated solely on the butterfly's speed. Understanding vector addition is crucial for solving these types of motion problems.
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Flying ButterFly---URGENT

Homework Statement


Monarch butterflies can sustain air speeds of 4.4 m/s while migrating. A certain monarch wants to fly to a location due west 4.7 km away. A steady 2.4 m/s breeze is blowing from the east to the west. How long will it take the monarch to make the trip to the location to the west?

If all conditions stay the same, how long would it take the monarch to make the return trip?

What is the total round trip flying time for the monarch? That is, how long would it take the butterfly to go to the west location, turn around, and come back?

What would the total round trip time be, if no wind was blowing?


Homework Equations



i don't know how to start solving the problem

The Attempt at a Solution



i don't know how to start solving the problem...
 
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its vectors quesitons...
draw a diagram out and label it this will give you a good start.
then its about adding vectors and using Newtons law of motion
 
Well you need to start somewhere...
Break up the trip into outbound and return flight.
With the breeze, will it take more or less time for the insect on the outbound trip compared to without a breeze?
 
Looks like one dimensional motion to me.
:cool:
 
first thing to realize that the wind velocity completely adds (or subtracts), so when aloft it is already moving at 2.4m/s. Add the velocitys carefully as determined by the direction. Then time=distance/speed. see what you can do.
 
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