Calculating Original Mass of Ice at 0 Degrees C

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The discussion revolves around calculating the original mass of ice at 0 degrees Celsius, which turns into water at the same temperature, gaining 1 kg of mass. The formula used is E_w - E_i = (m_w - m_i)c^2 = m_i*L, where L represents the specific latent heat. Participants clarify that this is primarily a mass-energy question, rather than one related to nuclear or particle physics. One user attempts to solve the equation and arrives at a mass of 2.67 x 10^11 kg, suggesting this result may be correct. The conversation emphasizes the importance of understanding the underlying principles of mass and energy in this context.
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The question is:
Ice at 0 degree C turns into Water at 0 degree C and thus gains 1 Kg of mass. What is the original mass of ice?
 
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Use E_w-E_i=(m_w-m_i)c^2=m_i*L, where L is the specific latent heat.
 
What has this to do with nuclear and particle physics?
 
malawi_glenn said:
What has this to do with nuclear and particle physics?

Let's just say that if you don't help sanphy, he'll go nuclear and physically smash you to particles.
 
Well this is indeed not a nuclear or particle physics question and is a mass-energy question.
I tried to solve but the mass comes out as 2.67 * 10^11 kg.
I think this could be correct.:approve::biggrin:
 
thanks clem
 

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