Calculating Particle Deceleration and Force | MCAT Physics Question 17

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Homework Help Overview

The discussion revolves around calculating the deceleration of a particle and the resulting force, as presented in a physics problem related to the MCAT. The subject area includes kinematics and dynamics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss methods for calculating deceleration using kinematic equations and then applying Newton's second law to find force. There is an exploration of numerical values and calculations, with one participant questioning the accuracy of their results.

Discussion Status

The discussion is active, with participants providing feedback on calculations and encouraging double-checking of results. There is an acknowledgment of potential errors in numerical input, but no consensus on the final answer has been reached.

Contextual Notes

Participants are working under the constraints of a specific MCAT physics question, which may impose certain assumptions or require specific approaches to problem-solving.

accol
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1. http://www.prep101.com/MCAT/102MCATPhysicsAnswers.pdf number 17


3. Here is my attempt:

First I figure I have to find the deceleration of the particle. So I plugged it into the v(final)^2= v(initial)^2 + 2ax. I solved for a and got a and got -240000.

I don't know if I am correct here but I plugged the accel and mass into F = ma and got a force of 1.608*10^-21N

I also tried substuting equations such as =

F = Eq
to ma = Eq but I still haven't gotten an answer along the lines of the choices. Please help me.

Thanks in advance.
 
Last edited by a moderator:
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accol said:
1. http://www.prep101.com/MCAT/102MCATPhysicsAnswers.pdf number 17


3. Here is my attempt:

First I figure I have to find the deceleration of the particle. So I plugged it into the v(final)^2= v(initial)^2 + 2ax. I solved for a and got a and got -240000.


You have the right idea, but I get a=-5.76 \times 10^{10} \text{m/s}^2. Double check your calculation :smile:
 
Last edited by a moderator:
Lol, wow...and I thought I was doing it all wrong, I just put the wrong numbers into the calculator. Thanks
 
Welcome :smile:
 

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