Calculating Potential Difference in a Uniform Electric Field | Example Problem

AI Thread Summary
The discussion focuses on calculating the potential difference between two points in a uniform electric field defined by E = (20000i - 50000j) V/m. The user attempts to apply the formula ΔV = -E·Δs, where Δs is the distance between the points, calculated as √(9cm)² + (1cm)². The user arrives at a potential difference of -4876.5 V but questions whether the angle of the electric field should be considered, suggesting the need for a dot product approach. The conversation highlights the importance of incorporating vector components in the calculation of potential difference in electric fields. Properly accounting for directionality in the electric field is crucial for accurate results.
KillerZ
Messages
116
Reaction score
0
I am wondering if I did this right.

Homework Statement



What is the potential difference between the points (x_i, y_i) = (0cm, -5cm) and (x_f, y_f) = (1cm, 4cm) in a uniform electric field equal to E = (20000i - 50000j) V/m ?

Homework Equations



\Delta V = V(s_{f})-V(s_{i}) = -\int^{s_{f}}_{s_{i}}E_{s}ds

E is uniform therefore:

\Delta V = - E_{s}\Delta s

\Delta s = \sqrt{(9cm)^{2}+(1cm)^{2}}

= \frac{\sqrt{82}}{100} m

E = \sqrt{(20000V/m)^{2}+(-50000V/m)^{2}}

= \sqrt{2.9*10^{9}} V/m

The Attempt at a Solution



\Delta V = - E_{s}\Delta s

= -(\sqrt{2.9*10^{9}} V/m)(\frac{\sqrt{82}}{100} m)

= -4876.5 V
 
Physics news on Phys.org
Don't you have to take the angle into account? Only a component of E is in the direction of the distance.
 
I think you take your

ΔV = E*Δs a little differently. Namely as the dot product of the E vector and the s vector, such that

ΔV = Ex*Δx i + Ey*Δy j
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top