Calculating Potential Energy Stored in Springs

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To calculate the potential energy stored in a spring with a mass of 10kg hanging from it, the spring constant is given as k=1000 N/m. The gravitational force acting on the mass is 100 N, which leads to a spring extension of 0.1 m using Hooke's Law. The potential energy stored in the spring can then be calculated using the formula PE = 1/2 kx^2, resulting in 5 joules. The discussion clarifies that the potential energy refers to the energy stored in the spring, not gravitational potential energy. The final calculation confirms that the energy stored in the spring is indeed 5 joules.
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A mass of 10kg hangs from an ideal (massless) spring from the ceiling. The mass and spring are in static equilibrium, so there is no motion. If the spring has a spring constant k=1000N/m and g = 10 m/s/s, what is the (potential) energy stored in the spring?



PE = mgh and KE(of spring)= 1/2kx^2 and maybe hooks law



Kind of stumped.

I am not sure how to go about this problem as I am not sure if it is a trick question. Since PE = mgh and there is no height here would the PE = 0? If I set PE = 1/2kx^2 I have one equation with two unknowns which does not help me. I want to say its a conservation of energy problem but I am not sure. Please help me understand.
 
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vysero said:
Since PE = mgh and there is no height here would the PE = 0?
It asks for the PE stored in the spring, not gravitational PE.
But you do need to work out the spring extension.
 
Ah okay so:

100N = 1000(x), x = .1

and (1/2)(1000)(.1)^2= 5 joules, is that right?
 
Looks right.
 
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