Calculating Potential of a Charged Plate: Figuring Out Fig. 23-1

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To calculate the potential difference between charged plates, one can use Gauss's Law to determine the electric field generated by the plates. Once the electric field is established, it can be integrated over the distance between the two plates to find the voltage. The discussion highlights that the electric field is constant in this scenario, simplifying the integration process. The need for a specific diagram, referred to as "Fig. 23-1," is noted, as it would provide necessary context for a more accurate analysis.
scilover89
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“We can see from our definition that the positive plate in Fig. 23-1 is at a higher potential than the negative plate..."

I saw this statement in a book. May I know how to calculate the potential of a charged plate?
 
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As always, the voltage between A and B is defined as a path integral of the electric field starting at point A and ending at point B. Of course, since the voltage is path independent you may integrate E over a straight line without loss of generality.
 
scilover89 said:
Quote:
“We can see from our definition that the positive plate in Fig. 23-1 is at a higher potential than the negative plate..."

I saw this statement in a book. May I know how to calculate the potential of a charged plate?

Use Gauss's Law to determin the electric field. Then integrate this electric field over the distance between the two plates; This is not that difficult since the E-field is constant; i AM ASSUMING TWO PLATES HERE
 
Could you present us with that "Fig. 23-1".It's kinda difficult to speculate,when we lack the data ...:-p


Daniel.

P.S.Well,at least for me it is...
 
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