Calculating Power & Energy of a Flashlight Bulb

AI Thread Summary
The power rating of the flashlight bulb can be calculated using the formula P = I * V, resulting in a power of 4.5 Watts. To find the energy converted in 11 minutes, it's important to understand that energy is the product of power and time. Since power is in Watts (Joules/second), the total energy in Joules can be calculated by multiplying the power by the total time in seconds (11 minutes equals 660 seconds). This means the energy converted by the lamp is 4.5 Watts multiplied by 660 seconds. The discussion emphasizes the relationship between power and energy in electrical systems.
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Homework Statement


a flashlight bulb is connected across a 3.0-V difference in potential. The current through the lamp is 1.5 A.
a. what is the power rating of the lamp?
b. how much electric energy does the lamp convert in 11 minutes?


Homework Equations


P=I*V


The Attempt at a Solution


a. P=(3.0)(1.5)
P=4.5
b.?
 
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Power, which is in Watts, is Joules/Seconds. Energy is described in Joules. Does this help?
 
To make it clearer to the OP, power is energy consumed in unit time.
 

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