Calculating Pressure at Different Altitudes and Depths

  • Thread starter Thread starter robertsa
  • Start date Start date
AI Thread Summary
The mountaineer measures air pressure at 10% below sea level, which corresponds to a height where the pressure is equivalent to 68.4 cm of mercury. This indicates an altitude of approximately 1,000 meters above sea level, based on standard atmospheric pressure calculations. At the deepest point of the 4.3m lake, the pressure can be calculated using the formula P = D*G*H, where the density of water is 1,000 kg/m^3. The total pressure at the lake's bottom includes both the water pressure and the atmospheric pressure. Accurate unit conversion is essential for correct calculations.
robertsa
Messages
10
Reaction score
0

Homework Statement



A mountaineer in the Rockies measures the air pressure to be 10% below that at sea level. At what height above sea level does he make the measurement? At this altitude he finds a small mountain lake of fresh water which is 4.3m deep at its deepest point. What is the pressure at the deepest point of the lake

Homework Equations



P-Po=density x g x distance?

The Attempt at a Solution

 
Physics news on Phys.org


Pressure at sea level = pressure due to 76 cm of mercury column.
10% less of this pressure is 68.4 cm of mercury column.
So the pressure at the mountain is ρ*g*h'. ρ is the density of the mercury.
 


For the 2nd part P = D*G*H. density of water = 1000kg/m^3. After you get the pressure you simply add the atmospheric pressure. P = Pg + Pa. Make sure your units are correct, throws me off a lot.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top