Calculating pressure at pressure relief valve outlet

AI Thread Summary
The discussion focuses on calculating the discharge pressure at the outlet of a Pressure Relief Valve (PRV) connected to an atmospheric vent. The PRV opens at a set pressure of 30 PSIG, with a flow capacity of 60,000 lb/hr, leading to calculations of volume flow rate, exit velocity, and pressure drop. A significant point raised is that the pressure at the vent outlet can exceed atmospheric pressure under critical flow conditions, which may not have been considered in initial calculations. It is emphasized that using the correct friction coefficient and downstream density is crucial for accurate pressure drop calculations. Ultimately, the pressure at the outlet can vary based on flow conditions, and reliance on a reliable supplier for calculations is recommended for safety in real applications.
smims
Messages
7
Reaction score
0
I have a tank which has a Pressure Relief Valve (PRV) connected to the atmospheric vent (Carbon steel with friction coefficient of 0.14). The PRV is opened at Set pressure of 30 PSIG and has a capacity of 60,000 SATSTM (I assumed it to be in lb/hr). I am trying to calculate the discharge pressure at the vent exit (opening).

The steps,

1. From steam table, specific volume of dry saturated steam at 30 PSIG = 9.5 cu.ft./lb
2. Calculating the volume flow rate at the exit = 60,000 x 9.5 = 570,000 cu.ft./hr = 158.33 cu.ft./sec
3. Calculating the nozzle outlet cross sectional area = 0.55 sq.ft. (Pipe nozzle diameter = 10 in = 0.83 ft)
4. Velocity at the exit = 158.33 x 0.55 = 290 ft/sec
5. Calculating pressure drop = (Friction coefficient/2) x (Pipe Length/Pipe Diameter) x (Velocity squared/gravity) = 0.14 x (10 ft /0.83 ft) x (290.35x290.35/32.17) = 2201 ft = 953 psi (Impossible!)

here is the excel file http://www.filedropper.com/prv_1

If I include the density in the above pressure drop calculation, the unit turns out to be in PSI than ft. But then I found no such equation that includes the density in calculating the pressure drop. What am I missing? Thanks.
 
Last edited:
Engineering news on Phys.org
Pressure at the outlet of the vent pipe will be equal to atmospheric pressure - 0 psig .
 
If you are working this as an exercise then Nidum can be considered close enough. If this is a real relief valve application you are better (and much safer) relying on a reliable supplier to do the calculation for you. Pressure at the outlet nozzle can be well above atmospheric pressure because a pressurized area will form at the outlet under actual relief.
 
I used a large Friction coefficient (3.5E-06 is the right one).
The pressure turned out to be 0.15 PSIG. So Nidum is right.

Thanks for your comments.
 
It's worth noting that it is possible for the pressure at your vent outlet to be higher than atmospheric pressure if you have critical flow. i.e mach 1 conditions at vent outlet. For the vent pressure drop you need to use the density at downstream pressure which will be be the backpressure created during relief which will less than the set pressure. It seems you have used the upstream density for your pressure drop calcs. First you need to check if the flow is critical at the vent outlet. If not your pressure at the outlet will be atmospheric. If it is then your pressure drop will be higher than atmospheric. Then you need to back calculate the pressure back to the relief valve outlet.
 
I need some assistance with calculating hp requirements for moving a load. - The 4000lb load is resting on ball bearing rails so friction is effectively zero and will be covered by my added power contingencies. Load: 4000lbs Distance to travel: 10 meters. Time to Travel: 7.5 seconds Need to accelerate the load from a stop to a nominal speed then decelerate coming to a stop. My power delivery method will be a gearmotor driving a gear rack. - I suspect the pinion gear to be about 3-4in in...
How did you find PF?: Via Google search Hi, I have a vessel I 3D printed to investigate single bubble rise. The vessel has a 4 mm gap separated by acrylic panels. This is essentially my viewing chamber where I can record the bubble motion. The vessel is open to atmosphere. The bubble generation mechanism is composed of a syringe pump and glass capillary tube (Internal Diameter of 0.45 mm). I connect a 1/4” air line hose from the syringe to the capillary The bubble is formed at the tip...
Thread 'Calculate minimum RPM to self-balance a CMG on two legs'
Here is a photo of a rough drawing of my apparatus that I have built many times and works. I would like to have a formula to give me the RPM necessary for the gyroscope to balance itself on the two legs (screws). I asked Claude to give me a formula and it gave me the following: Let me calculate the required RPM foreffective stabilization. I'll use the principles of gyroscopicprecession and the moment of inertia. First, let's calculate the keyparameters: 1. Moment of inertia of...
Back
Top