Calculating Pressure-Depth Relationship in the Pacific Ocean

AI Thread Summary
The discussion focuses on deriving an algebraic equation for the pressure-depth relationship in the Pacific Ocean, where seawater density increases non-linearly with depth. The density is expressed as p = p_o + m*z^2, with p_o being the surface density and m a constant. The attempt to relate pressure (P) to depth (z) involves integrating the density function and considering gravitational effects. The user acknowledges their initial approach is incorrect and seeks clarification on integrating the density to find pressure. The final suggestion points towards using the integral of density with respect to depth to calculate pressure accurately.
chimmy48
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Homework Statement



At a particular point in the Pacific Ocean, the density of sea water increases non-linearly with depth according to p = p_o + m*z^2
where p_o is the density at the surface, z is the depth below the surface, and m is a constant. Develop an algebraic equation for the relationship between pressure and depth.
p(represents density, not pressure), P represents pressure.

NB: ^ represents to the power of... (eg z^2 is z squared)

Homework Equations



p = p_o + m*z^z ...(1)

The Attempt at a Solution


P = p_o*gz;
p_o = P/gz;

then From (1):
p = (P/gz) + m*z^2
but p = m/v so
m/v = (P/gz) + m*z^2
mgz(1/v - z^2) = P

but F = mg

so

Fz(1/v - z^2) = P

I know this is wrong but i really need help!
 
Physics news on Phys.org
p(z) = p_o + m*z^2 ...(1)

Try dP(z) = p(z)g dz


Then P(h) = \int_0^h\,\rho(z)\,g\,dz
 
Thanks!
 

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