Calculating pressure given dia. and pounds

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To calculate the pressure required for a hydraulic lift with an 8-inch diameter cylinder to lift 6000 lbs, the area of the cylinder must first be determined using the formula A = π(r^2). The radius is 4 inches, leading to an area of approximately 50.265 square inches. Using the force of 6000 lbs, the pressure is calculated as 6000 lbs divided by the area, resulting in 119 psi, not the previously calculated 530.9 psi. It's emphasized that when working with pounds and inches, conversions to Newtons are unnecessary. Accurate calculations are crucial for proper hydraulic lift function.
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Homework Statement


the hydraulic lift for an automobile service garage has a cylinder with a diameter of 8 inches. What pressure must the oil have to be able to lift 6000 lbs?

Homework Equations


f=pa
area = pi(r^2)

The Attempt at a Solution


6000 lbs = 26 688 Newtons

8 inches = 3.14 x 16 = 50.265

26 688/50.265 = 530.9 psi (should be 119 psi)
 
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togo said:

Homework Statement


the hydraulic lift for an automobile service garage has a cylinder with a diameter of 8 inches. What pressure must the oil have to be able to lift 6000 lbs?


Homework Equations


f=pa
area = pi(r^2)


The Attempt at a Solution


6000 lbs = 26 688 Newtons
do not convert...leave in pounds of force
8 inches = 3.14 x 16 = 50.265
units...A = 50.265 in^2
26 688/50.265 = 530.9 psi (should be 119 psi)
If the problem is given in units of inches and pounds, do not convert pounds to Newtons.
 
thanks
 

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