Calculating Pressure Increase from Ice Expansion in an Engine Block

AI Thread Summary
When water freezes, it expands by approximately 9.10%, which can significantly increase pressure in an automobile engine block. The bulk modulus of ice is given as 2.00 x 10^9 N/m², leading to a calculated pressure increase of 1.82 x 10^8 Pa using the formula Delta P = -B*(Delta V)/V. The user notes that their answer is within 10% of the expected result but suspects a minor error in their calculations. They express confusion regarding the percentage decrease, indicating a misunderstanding of the relationship between the values. The discussion highlights the complexities of calculating pressure changes due to phase transitions in fluids.
zaqwer
Messages
1
Reaction score
0

Homework Statement



When water freezes, it expands about 9.10%. What would be the pressure increase inside your automobile engine block if the water in it froze? The bulk modulus of ice is 2.00 multiplied by 10^9 N/m2.


Homework Equations



Delta P=-B*(Delta V)/V

The Attempt at a Solution



Delta P= 2*10^9*.091
= 1.82*10^8 Pa

It says that the answer is within 10% of the correct answer however I don't know if there is a small error that is causing me to be slightly off.
 
Physics news on Phys.org
1.00 is not 9.10% less than 1.0910. Know what I mean?

EDIT: By the way, welcome to PF!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top