Calculating Pressure Inside a Water Mist Droplet

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The discussion centers on calculating the gauge pressure inside a spherical water mist droplet with a diameter of 0.1 mm using the formula delta P = 2 * surface tension / radius. The initial calculation yielded a pressure of 3000 Pa, which was incorrectly interpreted as 3 atm. Clarification was provided that 1 atm equals 100,000 Pa, leading to the corrected gauge pressure of 0.03 atm. Participants emphasized the importance of specifying units in calculations. The final consensus confirms that the calculated value is accurate when properly converted.
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Homework Statement


What's the gauge pressure inside a droplet of water mist of diameter 0.1 mm (radius 0.05 mm), assuming that the droplet is spherical? Use a water-air surface tension of 0.07 Jm\(^{-2}\) and specify your answer in bar /atmospheres (where 1 atmosphere pressure is \(1 \times 10^5\) Pa.

Homework Equations


delta P= 2*0.07/r (in meters)

The Attempt at a Solution


I subed the value inside the equation and i got 3000pa.. which is 3atm? am i right?
 
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Derek1997 said:

Homework Statement


What's the gauge pressure inside a droplet of water mist of diameter 0.1 mm (radius 0.05 mm), assuming that the droplet is spherical? Use a water-air surface tension of 0.07 Jm\(^{-2}\) and specify your answer in bar /atmospheres (where 1 atmosphere pressure is \(1 \times 10^5\) Pa.

Homework Equations


delta P= 2*0.07/r (in meters)

The Attempt at a Solution


I subed the value inside the equation and i got 3000pa.. which is 3atm? am i right?
It looks like you've chosen the correct formula to use, and your result in Pascals looks good to me for one significant figure of accuracy. Note however that an atm is not 1000 Pa; One atm is to be taken as 105 or 100,000 Pa according to the definition you're given in the problem statement.
 
so 0.03?
 
Derek1997 said:
so 0.03?
Yes, that looks like a good value. Be sure to always specify units on any values that you present!
 
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