Calculating Qf: Piano Key Frequency 256Hz Energy Dissipated in 1s

  • Thread starter Thread starter Eric_meyers
  • Start date Start date
AI Thread Summary
The discussion focuses on calculating the effective quality factor (Qf) of a piano key oscillating at 256 Hz, which loses half its energy in one second. The relevant equations include the exponential decay of energy and the formula for Qf, which is expressed as Qf = w/v. The user determined that the decay constant v is approximately 0.693, leading to a calculated Qf of around 369. There is some uncertainty regarding the energy dissipation calculation, but the approach using angular frequency appears to be correct. The conversation emphasizes the importance of correctly applying the formulas to achieve accurate results in energy dissipation calculations.
Eric_meyers
Messages
64
Reaction score
0

Homework Statement


"Systems typically exhibit an exponential decrease in their average stored energy of the form <E> = E_{0} e^(-vt) ---- If a piano key of frequency 256 Hz is struck and its oscillation energy decreases to one half of its initial value in about 1 second what is the effective Qf of the system?


Homework Equations



Qf = w/v
<E> = E_{0} e^(-vt)


The Attempt at a Solution



I need to find the energy dissipated and from the equation they gave me I put 1/2 (the energy the system has from its initial value after 1 second)

1/2 = e^(-v)

v = .693

Qf = 256/.693 = 369

I'm not quite sure if I did the dissipation energy equation correctly.
 
Physics news on Phys.org
Q=\frac{\omega}{v}=\frac{2 \pi f}{v}. Your numerator needs to be in angular frequency. Looks fine though.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top