Calculating Radius from Angular and Tangential Acceleration in a Bicycle Wheel

  • Thread starter Thread starter BoldKnight399
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
To calculate the radius of a bicycle wheel given an angular acceleration of 1.4 rad/s² and a tangential acceleration of 49 cm/s², the relationship between angular and tangential acceleration can be used. Tangential acceleration is defined as the product of angular acceleration and radius (a_t = α * r). Rearranging the formula provides the radius as r = a_t / α. Converting units from cm to meters is necessary for the final answer. This approach simplifies the problem and clarifies the relationship between the different types of acceleration in rotational motion.
BoldKnight399
Messages
78
Reaction score
0
A bicycle wheel has an angular acceleration
of 1.4 rad/s2.
If a point on its rim has a tangential accel-
eration of 49 cm/s2, what is the radius of the
wheel?
Answer in units of m.

I know that there should be some way to relate the angular acceleration and the tangential acceleration but I can't figure it out.

I tried to relate the angular acceleration to angular speed to then find delta theta so then I could plug into S=Rtheta. The only problem is that I don't have the angular speed. I know that there has to be an easy way to do this problem.


The Attempt at a Solution

 
Physics news on Phys.org
Welcome to PF!

Hail BoldKnight399! Welcome to PF! :smile:

(erm :redface: … tangential is more-or-less the opposite of centripetal :rolleyes:)
BoldKnight399 said:
… I know that there should be some way to relate the angular acceleration and the tangential acceleration but I can't figure it out.

cm/s2 = radian/s2 times cm/radian

(just like cm/s = radian/s times cm/radian :wink:).

So what is cm/radian in this case? :smile:
 
knew it had to be simple and I was just missing it. Thank you!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top